elahism的部落格

標題:

F.5Maths (circle) 20POINTS!!!!

發問:

please view the file below, thx. Give detailed steps please. https://www.dropbox.com/s/u1dypiz5h8v7cj6/circle%20mc.doc

• 交通罰款投訴
• 不知點解我做左幾日工變得好有禮貌!!
• [MPH2]轟龍太刃一問@1@

此文章來自奇摩知識+如有不便請留言告知

最佳解答:

87Q53 From the the Angle at the Center Theorem, a+b=(360- c )/ 2 = 180- c/2 90Q39 From Angle at the Center Theorem, tan 30 = BC/AC =1/√3 and BC*AC=2√3 AC=√6 cos 30=AC/AB=√3/2=√6/AB AB=√6/(√3/2)=2√2 radius=√2 2013-11-10 10:39:44 補充： 92Q50 By Alternate Segment Theorem ∠ADE= ∠ECD ∠CDE=180-24-3∠ADE=52 ∠DCB=90-52=38 (Angle in semicircle)

其他解答: