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標題:
Factorize x^3+y^3+x+y
發問:
如題~幫幫忙
x^3+y^3+x+y = (x+y)^3 - 3(x^2)y - 3x(y^2) + x + y = (x+y)^3 + x + y - 3xy(x+y) = (x+y) [ (x+y)^2 + 1 - 3xy ] = (x+y)( x^2 + 2xy + y^2 - 3xy ) = (x+y)(x^2-xy+y^2)
其他解答:
x^3+y^3+x+y =(X+Y)(X^2-XY+Y^2)+X+Y =(X+Y)(X^2-XY+Y^2+1)
Factorize x^3+y^3+x+y
發問:
如題~幫幫忙
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最佳解答:x^3+y^3+x+y = (x+y)^3 - 3(x^2)y - 3x(y^2) + x + y = (x+y)^3 + x + y - 3xy(x+y) = (x+y) [ (x+y)^2 + 1 - 3xy ] = (x+y)( x^2 + 2xy + y^2 - 3xy ) = (x+y)(x^2-xy+y^2)
其他解答:
x^3+y^3+x+y =(X+Y)(X^2-XY+Y^2)+X+Y =(X+Y)(X^2-XY+Y^2+1)
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