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問PHY 1998 CE MC Q.10 AND Q.11 可唔可以解釋下個答案問黎?
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10. Since the inclined plane is smooth, so there is no work done against friction. So, by the law of conservation of energy, the energy output by the man = potential energy gained by the box = (50)(10)(6sin30°) = 1500 J Power = energy / time = 1500 / 30 = 50 W So, the answer is C. 11. This is a question concerning moment, which is out of CE syllabus.
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問PHY 1998 CE MC Q.10 AND Q.11發問:
問PHY 1998 CE MC Q.10 AND Q.11 可唔可以解釋下個答案問黎?
最佳解答:
10. Since the inclined plane is smooth, so there is no work done against friction. So, by the law of conservation of energy, the energy output by the man = potential energy gained by the box = (50)(10)(6sin30°) = 1500 J Power = energy / time = 1500 / 30 = 50 W So, the answer is C. 11. This is a question concerning moment, which is out of CE syllabus.
其他解答:
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