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指數函數 & 對數函數 MC (20點)
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圖片參考:http://imgcld.yimg.com/8/n/HA00230702/o/701106180079413873460705.jpg 教我做...唔該哂 33,35題請解釋 答案 : 37. C 35. C 39.B 33. C 40. A 2. C 更新: 37. 我唔明點解 x^(1/n + 1/mn) = x^(m+1/mn) 35題唔明你嘅解釋 33. a^x1 = b^x2 log a^x1 = log b^x2 x1 log a = x2 log b x1 / x2 = log b / log a x2必定不正確 ...... 答案選 C
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37. 原式 = {x*[x^(1/m)]}^(1/n) = {x^[1 + (1/m)]}^(1/n) = x^[(1/n) + (1/mn)] = x^[(m + 1)/mn] ...... 答案選 C ===== 35. 令 a = log x 0 因此 0 x2必定不正確 ...... 答案選 C ===== 40. log2x = log2(8y)2 = log2(8) + log2(y)2 = log2(2)3 + 2log2y = 2log2y + 3log22 = 2log2y + 3 ...... 答案選 A ===== 2. 2^2n * 9^n / 3^n = 2^2n * (3^2)^n / 3^n = (2^2)^n * 3^2n / 3^n = 4^n * 3^(2n - n) = 4^n * 3^n = (4 * 3)^n = 12^n ...... 答案選 C 2011-06-18 23:43:55 補充: 37. x^(1/n + 1/mn) = x^(m/mn+1/mn) = x^[(m+ 1)/mn] 35. 設 a = log x 根據 log 的定義 x = 10^a 因 log x 0 ... (2) 根據 (1) 和 (2): 0
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