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Form 3 maths (urgent)
1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Ans: 63.1 cm^2 (steps)2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? Ans: 425 cm^3 3.Given two right cylindrical vessels A and B. The base... 顯示更多 1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Ans: 63.1 cm^2 (steps) 2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? Ans: 425 cm^3 3.Given two right cylindrical vessels A and B. The base diameters of vessels A and B are 4cm and 12cm respectively. Initially, A contains water to a depth of 18cm and B is empty. The water in A is then poured into B .Find (a) the water level in B , (b) the wetted surface area of B Ans:(a)2 sm (b)188cm^2
最佳解答:
1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Let r cm be the radius of the quadrant. r + r + (1/4)(2πr) = 32 r + r + (1/2)(3.14r) = 32 3.57r = 32 r = (32/3.57) Area enclosed by the wire = (1/4)πr2 = (1/4)(3.14)(32/3.57)2 cm2 = 63.1 cm2 2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? The water coming out is in a form of cylinder. Radius of the water cylinder, r = 2.6/2 cm2 = 1.3 cm2 Height of the water cylinder, h = 0.8 m = 0.8 x 100 cm = 80 cm Water coming out per second = πr2h = 3.14 x (1.3)2 x 80 cm3 = 425 cm3 3.Given two right cylindrical vessels A and B. The base diameters of vessels A and B are 4cm and 12cm respectively. Initially, A contains water to a depth of 18cm and B is empty. The water in A is then poured into B .Find (a) the water level in B , (b) the wetted surface area of B Ans:(a)2 sm (b)188cm^2 (a) Volume of water = π x (4/2)2 x 18 cm3 = 72π cm3 Water level in B = 72π / [π x (12/2)2] cm = 2 cm (b) The wetted surface area of B = Base area of B + Area of the wetted inner wall of B = [π x (12/2)2 + π x 12 x 2] cm2 = 3.14 x 60 cm2 = 188 cm2
其他解答:CF546184A985CA23
Form 3 maths (urgent)
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發問:1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Ans: 63.1 cm^2 (steps)2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? Ans: 425 cm^3 3.Given two right cylindrical vessels A and B. The base... 顯示更多 1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Ans: 63.1 cm^2 (steps) 2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? Ans: 425 cm^3 3.Given two right cylindrical vessels A and B. The base diameters of vessels A and B are 4cm and 12cm respectively. Initially, A contains water to a depth of 18cm and B is empty. The water in A is then poured into B .Find (a) the water level in B , (b) the wetted surface area of B Ans:(a)2 sm (b)188cm^2
最佳解答:
1. A wire, 32 cm long, is bent into the shape of a quadrant. Find the area enclosed by the wire. Let r cm be the radius of the quadrant. r + r + (1/4)(2πr) = 32 r + r + (1/2)(3.14r) = 32 3.57r = 32 r = (32/3.57) Area enclosed by the wire = (1/4)πr2 = (1/4)(3.14)(32/3.57)2 cm2 = 63.1 cm2 2. A water pipe of internal diameter 2.6cm delievers water at rate od 0.8 m/s .How much water comes out per second ? The water coming out is in a form of cylinder. Radius of the water cylinder, r = 2.6/2 cm2 = 1.3 cm2 Height of the water cylinder, h = 0.8 m = 0.8 x 100 cm = 80 cm Water coming out per second = πr2h = 3.14 x (1.3)2 x 80 cm3 = 425 cm3 3.Given two right cylindrical vessels A and B. The base diameters of vessels A and B are 4cm and 12cm respectively. Initially, A contains water to a depth of 18cm and B is empty. The water in A is then poured into B .Find (a) the water level in B , (b) the wetted surface area of B Ans:(a)2 sm (b)188cm^2 (a) Volume of water = π x (4/2)2 x 18 cm3 = 72π cm3 Water level in B = 72π / [π x (12/2)2] cm = 2 cm (b) The wetted surface area of B = Base area of B + Area of the wetted inner wall of B = [π x (12/2)2 + π x 12 x 2] cm2 = 3.14 x 60 cm2 = 188 cm2
其他解答:CF546184A985CA23
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